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Regular Expressions to Validate ISBN Code

 1 year ago
source link: https://www.geeksforgeeks.org/regular-expressions-to-validate-isbn-code/?utm_campaign=newhomepage
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Regular Expressions to Validate ISBN Code

  • Last Updated : 15 Dec, 2022

Given some ISBN Codes, the task is to check if they are valid or not using regular expressions. Rules for the valid codesare:

  • It is a unique 10 or 13-digit.
  • It may or may not contain a hyphen.
  • It should not contain whitespaces and other special characters.
  • It does not allow alphabet letters.

Examples:

Input: str = ”978-1-45678-123-4″
Output: True

Input: str = ”ISBN446877428FCI″
Output: False
Explanation: It should contain digits and hyphens only.

Approach: The problem can be solved based on the following idea:

Create a regex pattern to validate the number as written below:   
regex = ^(?=(?:[^0-9]*[0-9]){10}(?:(?:[^0-9]*[0-9]){3})?$)[\d-]+$

Where,

  • ^: Represents the beginning of the string.
  • ?: Either it contains or not.
  • $: Ending of the string.

Follow the below steps to implement the idea:

  • Create a regex expression for ISBN Codes.
  • Use Pattern class to compile the regex formed.
  • Use the matcher function to check whether the ISBN Codes is valid or not.
  • If it is valid, return true. Otherwise, return false.

Below is the implementation of the above approach.

  • Python3
  • Javascript
// Java program to validate the
// ISBN Code using Regular Expression
import java.util.regex.*;

class GFG {

    // Function to validate the
    // ISBN Code
    public static boolean isValidISBNCode(String str)
    {

        // Regex to check valid ISBN Code
        String regex
            = "^(?=(?:[^0-9]*[0-9]){10}(?:(?:[^0-9]*[0-9]){3})?$)[\\d-]+$";

        // Compile the ReGex
        Pattern p = Pattern.compile(regex);

        // If the str
        // is empty return false
        if (str == null) {
            return false;
        }

        // Pattern class contains matcher() method
        // to find matching between given
        // str using regular expression.
        Matcher m = p.matcher(str);

        // Return if the str
        // matched the ReGex
        return m.matches();
    }

    // Driver Code.
    public static void main(String args[])
    {

        // Test Case 1:
        String str1 = "978-1-45678-123-4";
        System.out.println(isValidISBNCode(str1));

        // Test Case 2:
        String str2 = "1-56619-909-3";
        System.out.println(isValidISBNCode(str2));

        // Test Case 3:
        String str3 = "1207199818865";
        System.out.println(isValidISBNCode(str3));

        // Test Case 4:
        String str4 = "978-1-12345-909-4 2";
        System.out.println(isValidISBNCode(str4));

        // Test Case 5:
        String str5 = "ISBN446877428FCI";
        System.out.println(isValidISBNCode(str5));
    }
}
Output
true
true
true
false
false

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