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Regex stops at first occurrence in java

 3 years ago
source link: https://www.codesd.com/item/regex-stops-at-first-occurrence-in-java.html
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Regex stops at first occurrence in java

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I think there is a problem with my regex because when I looked for resolve my problem, I found only question about wanted to stop at the first occurrence. Although, I want my regex to go after the first occurrence.

Here is my code:

String test = "\\d";
String word = "a1ap1k7";

Pattern p = Pattern.compile(test);
Matcher b = p.matcher(word);

if (b.find()) {
    int start = b.start();
    String text = b.group();
    int stop = b.end();
    System.out.println(start + text + stop);
}

It gives me just: 1(for the start)1(for the text)2(for the end)

You made just a simple error in writing this. You have to keep calling find

public static void main(String[] args){

    String test = "\\d";
    String word = "a1ap1k7";

    Pattern p = Pattern.compile(test);
    Matcher b = p.matcher(word);

    while (b.find())
    {
        int start = b.start();
        String text = b.group();
        int stop = b.end();
        System.out.println(start + text + stop);
    }
}

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