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使用urlliib.parse库解析url

 2 years ago
source link: https://www.lujun9972.win/blog/2018/02/22/%E4%BD%BF%E7%94%A8urlliib.parse%E5%BA%93%E8%A7%A3%E6%9E%90url/index.html
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解析url

urlparse() 函数可以将url解析成 ParseResult 对象. 对象中包含了六个元素,分别为:

  • 协议(scheme)
  • 域名(netloc)
  • 路径(path)
  • 路径参数(params)
  • 查询参数(query)
  • 片段(fragment)
from urllib.parse import urlparse

url='http://user:pwd@domain:80/path;params?query=queryarg#fragment'

parsed_result=urlparse(url)

print('parsed_result包含了',len(parsed_result),'个元素')
print(parsed_result)
parsed_result包含了 6 个元素
ParseResult(scheme='http', netloc='user:pwd@domain:80', path='/path', params='params', query='query=queryarg', fragment='fragment')

ParseResult 继承于 namedtuple, 因此既可以同时通过索引和命名属性来获取URL中各部分的值

为了方便起见, ParseResult 还提供了 username, password, hostname, portnetloc 进一步进行拆分。

print('scheme  :', parsed_result.scheme)
print('netloc  :', parsed_result.netloc)
print('path    :', parsed_result.path)
print('params  :', parsed_result.params)
print('query   :', parsed_result.query)
print('fragment:', parsed_result.fragment)
print('username:', parsed_result.username)
print('password:', parsed_result.password)
print('hostname:', parsed_result.hostname)
print('port    :', parsed_result.port)
scheme  : http
netloc  : user:pwd@domain:80
path    : /path
params  : params
query   : query=queryarg
fragment: fragment
username: user
password: pwd
hostname: domain
port    : 80

除了 urlparse() 之外,还有一个类似的 urlsplit() 函数也能对URL进行拆分,所不同的是, urlsplit() 并不会把 路径参数(params)路径(path) 中分离出来。

当URL中path部分包含多个参数时,使用 urlparse() 解析是有问题的

url='http://user:pwd@domain:80/path1;params1/path2;params2?query=queryarg#fragment'

parsed_result=urlparse(url)

print(parsed_result)
print('parsed.path    :', parsed_result.path)
print('parsed.params  :', parsed_result.params)
ParseResult(scheme='http', netloc='user:pwd@domain:80', path='/path1;params1/path2', params='params2', query='query=queryarg', fragment='fragment')
parsed.path    : /path1;params1/path2
parsed.params  : params2

这时可以使用 urlsplit() 来解析

from urllib.parse import urlsplit
split_result=urlsplit(url)

print(split_result)
print('split.path    :', split_result.path)
# SplitResult 没有params属性
SplitResult(scheme='http', netloc='user:pwd@domain:80', path='/path1;params1/path2;params2', query='query=queryarg', fragment='fragment')
split.path    : /path1;params1/path2;params2

若只是要将URL后的fragment标识拆分出来,可以使用 urldefrag() 函数

from urllib.parse import urldefrag

url = 'http://user:pwd@domain:80/path1;params1/path2;params2?query=queryarg#fragment'

d = urldefrag(url)
print(d)
print('url     :', d.url)
print('fragment:', d.fragment)
DefragResult(url='http://user:pwd@domain:80/path1;params1/path2;params2?query=queryarg', fragment='fragment')
url     : http://user:pwd@domain:80/path1;params1/path2;params2?query=queryarg
fragment: fragment

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