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Trying to get the year out of a date with sed

 3 years ago
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Trying to get the year out of a date with sed

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This question already has an answer here:

  • Why doesn't `\d` work in regular expressions in sed? 3 answers

I'm using the following command to get the year out of a string using sed.

echo 1234-1-12 | sed -r 's/(\d{4})-\d{1,2}-\d{1,2}/\1/'

but somehow it returns the entire date instead of the year.

getting 1234-1-12

expecting 1234

Any ideas why it doesn't work?

Simple grep approach:

echo "1234-1-12" | grep -o '^[^-]*'

The output:

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