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喝汽水--C语言_wx61f0a33ec5047的技术博客_51CTO博客
source link: https://blog.51cto.com/u_15501985/5916391
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题目名称：
喝汽水问题
题目内容：
喝汽水，1瓶汽水1元，2个空瓶可以换一瓶汽水，给20元，可以多少汽水（编程）
1.20元能喝20瓶
2.2个空瓶能换1瓶汽水，剩下的空瓶：empty/2+empty%
#include<stdio.h>
int main()
{
int money = 0;
int total = 0;
int empty = 0;
scanf("%d", &money);
total = money;
empty = money;
while (empty > 1)
{
total += empty / 2;
empty = empty / 2 + empty % 2;
}
printf("%d", total);
return 0;
}
int main()
{
int money = 0;
int total = 0;
int empty = 0;
scanf("%d", &money);
total = money;
empty = money;
while (empty > 1)
{
total += empty / 2;
empty = empty / 2 + empty % 2;
}
printf("%d", total);
return 0;
}
方法2：（由方法1得等差数列（empty*2-1））
#include<stdio.h>
int main()
{
int money = 0;
int total = 0;
int empty = 0;
scanf("%d", &money);
total = money;
empty = money;
if (empty > 0)
total = empty * 2 - 1;
return 0;
}
int main()
{
int money = 0;
int total = 0;
int empty = 0;
scanf("%d", &money);
total = money;
empty = money;
if (empty > 0)
total = empty * 2 - 1;
return 0;
}
没有撤退可言
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