6
#yyds干货盘点# LeetCode程序员面试金典：字符串轮转
source link: https://blog.51cto.com/u_13321676/5913094
Go to the source link to view the article. You can view the picture content, updated content and better typesetting reading experience. If the link is broken, please click the button below to view the snapshot at that time.
#yyds干货盘点# LeetCode程序员面试金典：字符串轮转
精选 原创字符串轮转。给定两个字符串s1和s2，请编写代码检查s2是否为s1旋转而成（比如，waterbottle是erbottlewat旋转后的字符串）。
输入：s1 = "waterbottle", s2 = "erbottlewat"
输出：True
输入：s1 = "aa", s2 = "aba"
输出：False
代码实现：
class Solution {
public boolean isFlipedString(String s1, String s2) {
int m = s1.length(), n = s2.length();
if (m != n) {
return false;
}
if (n == 0) {
return true;
}
for (int i = 0; i < n; i++) {
boolean flag = true;
for (int j = 0; j < n; j++) {
if (s1.charAt((i + j) % n) != s2.charAt(j)) {
flag = false;
break;
}
}
if (flag) {
return true;
}
}
return false;
}
}
public boolean isFlipedString(String s1, String s2) {
int m = s1.length(), n = s2.length();
if (m != n) {
return false;
}
if (n == 0) {
return true;
}
for (int i = 0; i < n; i++) {
boolean flag = true;
for (int j = 0; j < n; j++) {
if (s1.charAt((i + j) % n) != s2.charAt(j)) {
flag = false;
break;
}
}
if (flag) {
return true;
}
}
return false;
}
}
Recommend
About Joyk
Aggregate valuable and interesting links.
Joyk means Joy of geeK