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C program to find the second most frequent charecter in a string

 3 years ago
source link: https://www.codeproject.com/Questions/5318674/C-program-to-find-the-second-most-frequent-charect
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we have to find the second most occuring charecter in a string

What I have tried:
Copy Code
#include<stdio.h>
#include<string.h>
void main()
{
	char s[20];
	int count[20]={0},i,first=0,second=0;
	for(i=0;s[i];i++)
	{
		count[s[i]]++;
	}
	for(i=0;i<20;i++)
	{
		if(count[i]>count[first])
		{
			second=first;
			first=i;
		}
		else if(count[i]>count[second]&&count[i]!=count[first])
		{
		 second=i;	
		}
		printf("second most frequent charecter is %c",second);
	}
Comments
What is the problem?
Maybe this will get you started:
Expand ▼   Copy Code
#include<stdio.h>
#include<string.h>

int main()
{
	char s[] = "abca";
	int count[20], i, j, len, first = 0, second = 0;
	
	len = strlen(s);

	for (i=0; i < len; i++)
	{
	    count[i] = 0;
	    
		for (j=0; j < len; j++)
		{
			if (s[i] == s[j])
			{
				count[i]++;
			}
		}
    }
	
	for (i=0; i < len; i++)
	{
		if (count[i] > count[first])
		{
			first = i;
		}
	}
	
	printf("Most frequent character is = %c\n", s[first]);
}

Note that the outcome will not be correct if you have characters with an equal count,
e.g. a string like "abab".

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