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How to return the list index to Python
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How to return the list index to Python
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This question already has an answer here:
- Accessing the index in Python 'for' loops 12 answers
I have a list U of lists such that U=[a[1], a[2], a[3]] and where a = [[0,1,2], [0,0,0],[1,1,1]]. I am trying to change U in a way that it will only contain lists without 2. I know that if I want U = [a[2], a[3]] I have to do it like this:
for j in range (0,2):
U= [f for f in U if f[j]!=2]
But now I want it to return only the index of the lists, I mean at the end U should be [2,3]. Is it possible to do it ?
Thanks for the help !
Use enumerate:
>>> a = [[0,1,2],[0,0,0],[1,1,1]]
>>> [i for i, x in enumerate(a, 1) if 2 not in x]
[2, 3]
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