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Java 获取本机的外网 IP

 2 years ago
source link: https://segmentfault.com/a/1190000040742660
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Java 获取本机的外网 IP

发布于 45 分钟前

通过 HTTP 访问第三方获取 IP 的服务接口获取本机的外网 IP,例如:

考虑到这些第三方接口不一定 100% 稳定,例如可能出现下线、错误、访问超时或太慢的情况,所以不能仅依赖其中之一。

下面提供一种方案,并发访问这些服务接口,并返回第一个成功的结果,也就是其中最快的一个返回结果。

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.*;
import java.util.regex.Pattern;

public class ExternalIPUtil {

    /**
     * IP 地址校验的正则表达式
     */
    private static final Pattern IPV4_PATTERN = Pattern.compile("^(([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([01]?\\d\\d?|2[0-4]\\d|25[0-5])$");

    /**
     * 获取 IP 地址的服务列表
     */
    private static final String[] IPV4_SERVICES = {
            "http://checkip.amazonaws.com/",
            "https://ipv4.icanhazip.com/",
            "http://bot.whatismyipaddress.com/"
            // and so on ...
    };

    public static String get() throws ExecutionException, InterruptedException {
        List<Callable<String>> callables = new ArrayList<>();
        for (String ipService : IPV4_SERVICES) {
            callables.add(() -> get(ipService));
        }

        ExecutorService executorService = Executors.newCachedThreadPool();
        try {
            // 返回第一个成功获取的 IP
            return executorService.invokeAny(callables);
        } finally {
            executorService.shutdown();
        }
    }

    private static String get(String url) throws IOException {
        try (BufferedReader in = new BufferedReader(new InputStreamReader(new URL(url).openStream()))) {
            String ip = in.readLine();
            if (IPV4_PATTERN.matcher(ip).matches()) {
                return ip;
            } else {
                throw new IOException("invalid IPv4 address: " + ip);
            }
        }
    }
}

线程池的 ExecutorService.invokeAny(callables) 方法用于并发执行多个线程,并拿到最快的执行成功的线程的返回值,只要有一个执行成功,其他失败的任务都会忽略。但是如果全部失败,例如本机根本就没有连外网,那么就会抛出 ExecutionException 异常。

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