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(Python) Dictionary divided into two based on a property

 3 years ago
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(Python) Dictionary divided into two based on a property

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I want to split a dictionary in two based on whether any of an array of strings is present in a property within the main dictionary. Currently I can achieve this with two separate dictionary comprehensions (below), but is there a more efficient way to do this with only one line/dictionary comprehension?

included = {k:v for k,v in users.items() if not any(x.lower() in v["name"].lower() for x in EXCLUDED_USERS)}
excluded = {k:v for k,v in users.items() if any(x.lower() in v["name"].lower() for x in EXCLUDED_USERS)}

EDIT

EXCLUDED_USERS contains a list of patterns.

One line solution (with lower_excluded_users which I couldn't resist making)

included, excluded = dict(), dict()

# ssly, you don't have to do this everytime
lower_excluded_users = [x.lower() for x in EXCLUDED_USERS]

# and now the one-line answer using if-else-for construct with
# v substituted by D[k]. And instead of using `for k, v in dicn.items()`
# I have used [... for aKey in dicn.keys()]

[ excluded.update({aKey: users[aKey]}) \
    if any(x in users[aKey]["name"].lower() for x in lower_excluded_users) \
    else \
    included.update({aKey: users[aKey]}) \
    for aKey in users.keys()
]

Or one without beautification:

[excluded.update({aKey: users[aKey]}) if any(x in users[aKey]["name"].lower() for x in lower_excluded_users) else included.update({aKey: users[aKey]}) for aKey in users.keys()]

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