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How to divide a data frame into a list of data frames that have given column nam...

 3 years ago
source link: https://www.codesd.com/item/how-to-divide-a-data-frame-into-a-list-of-data-frames-that-have-given-column-names.html
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How to divide a data frame into a list of data frames that have given column names?

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I would like to build a function, something like splitdf(columnA + columnB ~ ., dataframe)

So that it would return a list of sub data frames for each possible pair of columnA and columnB. It is similar to table or xtabs

So, for

> a <- data.frame(x=1:3, y=1:3, z=1:9)
> a
  x y z
1 1 1 1
2 2 2 2
3 3 3 3
4 1 1 4
5 2 2 5
6 3 3 6
7 1 1 7
8 2 2 8
9 3 3 9

I am expecting:

x = 1, y = 1,
      x y z
     1 1 1
     1 1 4
     1 1 7

x = 2, y = 2,
      x y z
     2 2 2
     2 2 5
     2 2 8

x = 3, y = 3,
      x y z
     3 3 3
     3 3 6
     3 3 9

Update

I realized that split and dlply could work. However neither of them provide me with a good way to manipulate category names? How do I make these names to be meaningful? Like I would like to see x = 1, y = 1 instead of $1.1

Is this what you want?

> library (plyr)
> dlply(a, .(x, y))
$`1.1`
  x y z
1 1 1 1
2 1 1 4
3 1 1 7

$`2.2`
  x y z
1 2 2 2
2 2 2 5
3 2 2 8

$`3.3`
  x y z
1 3 3 3
2 3 3 6
3 3 3 9

update

> z <- dlply(a, .(x, y))
> names(z) <- dlply(a, .(x, y), function(x) sprintf("x = %d, y = %d", x$x[1], x$y[1]))
> z
$`x = 1, y = 1`
  x y z
1 1 1 1
2 1 1 4
3 1 1 7

$`x = 2, y = 2`
  x y z
1 2 2 2
2 2 2 5
3 2 2 8

$`x = 3, y = 3`
  x y z
1 3 3 3
2 3 3 6
3 3 3 9

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