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sizeof 计算问题求解

 2 years ago
source link: https://www.v2ex.com/t/789496
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V2EX  ›  C

sizeof 计算问题求解

  JQiue · 1 小时 17 分钟前 · 244 次点击 
void foo(int *arr) {
  printf("%d\n", sizeof arr); // 4
}

int main(){
  int arr[] = {1, 2, 3, 4, 5};
  printf("%d\n", sizeof arr); // 20
  foo(arr);
}

对于上述代码的sizeof计算数组字节结果有些不太明白，arr很显然和arr[0]是等效的，为什么在主函数中计算arr的大小等于20（所有元素加起来的字节大小），而作为参数传递给另一个函数时却是4？


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