Bash no parameters for $ (function parameters)

I want to create a script that use basic (prompt and confirm) functions multiple times, when I try to set the return to any variable the function ignore the parameters

function promp() {
    echo $*
    read response
    echo $response
}
function confirm() {
    echo $*
    read -rp $'(y/N) : ' -ei $'N' key;
    case "$key" in
        [yY][eE][sS]|[yY])
            echo true
            ;;
        *)
            echo false
            ;;
    esac
}

IS_RESPONSE=$(confirm "SOME QUESTION")
STRING_RESPONSE=$(promp "WRITE SOMETHING")
echo $IS_RESPONSE
echo $STRING_RESPONSE

Expected:

SOME QUESTION
(y/N) : N
WRITE SOMETHING
#<< "some text"
false
some text

Obtained:

(y/N) : N
#<< "some text"
SOME QUESTION false
WRITE SOMETHING some text

I know the problem is the echo within the function is part of the variable data, but I want to get this printed.

How can I do this or which is the best way to do this

Your functions are called in context of command substitution:

STRING_RESPONSE=$(promp "WRITE SOMETHING")

So the standard output of the promp "WRITE SOMETHING" command is attached to the context of the variable assignment.

However, the standard error is still attached to the terminal. If you redirect the output of echo to the file descriptor 2, then the output will be displayed to the user just when the echo is called, e.g.:

function promp() {
    echo >&2 "$*"
    read response
    echo "$response"
}

Another way is to use -p option: read -p "Your prompt: " which prints the prompt string to the standard error as well.