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Codeforces607B Zuma(区间DP)
source link: https://arminli.com/cf607b/
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Armin's Blog
Codeforces607B Zuma(区间DP)
March 03, 2016
题意:长为 n 的序列,每次可以删除一个回文子串,删除之后两边合并起来,问最少几次可以将序列删完。
dp[l][r] 表示[l, r]区间内最少次数,s[l] ==s[r]时,dp[l][r] = dp[l+1][r-1]。
#include<cstring> #include<cstdio> #include<cstring> #include<cmath> #include<string> #include<iostream> #include<algorithm> using namespace std; int dp[505][505]; int s[505]; int solve(int l, int r){ if(l == r) return 1; if(l > r) return 0; if(dp[l][r] > 0) return dp[l][r]; int ret = 505; for(int i = l; i < r; i++){ ret = min(ret, solve(l, i)+solve(i+1, r)); } if(s[l] == s[r]) ret = min(ret, max(1, solve(l+1, r-1))); dp[l][r] = ret; return ret; } int main(){ //freopen("a.txt", "r", stdin); int n; while(scanf("%d", &n) != EOF){ memset(dp, 0, sizeof(dp)); for(int i = 1; i <= n; i++) scanf("%d", &s[i]); cout << solve(1, n) << endl; } return 0; }
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