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【d3】link nodes by name | iTimeTraveler

 3 years ago
source link: https://itimetraveler.github.io/2016/11/16/%E3%80%90D3%E3%80%91Link%20Nodes%20by%20Name/
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【D3】Link Nodes by Name

Source : http://bl.ocks.org/mbostock/533daf20348023dfdd76

This example shows how to link nodes in a force-directed graph using a named identifier rather than a numeric index.

# index.html

<!DOCTYPE html>
<meta charset="utf-8">
<style>

.node {
stroke: #000;
stroke-width: 1.5px;
}

.link {
stroke: #999;
stroke-width: 1.5px;
}

</style>
<svg width="960" height="500"></svg>
<script src="//d3js.org/d3.v4.min.js"></script>
<script>

var svg = d3.select("svg"),
width = +svg.attr("width"),
height = +svg.attr("height");

var simulation = d3.forceSimulation()
.force("charge", d3.forceManyBody().strength(-200))
.force("link", d3.forceLink().id(function(d) { return d.id; }).distance(40))
.force("x", d3.forceX(width / 2))
.force("y", d3.forceY(height / 2))
.on("tick", ticked);

var link = svg.selectAll(".link"),
node = svg.selectAll(".node");

d3.json("graph.json", function(error, graph) {
if (error) throw error;

simulation.nodes(graph.nodes);
simulation.force("link").links(graph.links);

link = link
.data(graph.links)
.enter().append("line")
.attr("class", "link");

node = node
.data(graph.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 6)
.style("fill", function(d) { return d.id; });
});

function ticked() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });

node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
}

</script>

# graph.json

{
"nodes": [
{"id": "red"},
{"id": "orange"},
{"id": "yellow"},
{"id": "green"},
{"id": "blue"},
{"id": "violet"}
],
"links": [
{"source": "red", "target": "yellow"},
{"source": "red", "target": "blue"},
{"source": "red", "target": "green"}
]
}

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