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Python中如何实现日期字符串(datetimes)相减
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2020年12月31日2020年12月31日
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by YoungTimes
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Python中如何实现日期字符串(datetimes)相减
在日志系统中每条日志前一般都会带上毫秒级的时间戳，为了统计某部分代码的耗时，我们需要将两个时间戳相减，从而得到耗时分布，指导我们针对性的优化代码实现。
时间戳的示例如下：
2015-08-10 19:33:27.653
2015-08-10 19:31:28.209
2015-08-10 19:33:27.653 2015-08-10 19:31:28.209
在Python中如何将这两个字符串的日期相减呢？
from datetime import datetime
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
from datetime import datetime
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
程序输出：
0:01:59.444000
0:01:59.444000
这个时间差值不够友好，要是能得到秒级的耗时就更加直接了，比如从A到B耗时0.1s，从B到C耗时0.8s等等。如何得到秒级的耗时呢？
from datetime import datetime
from datetime import timedelta
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
delta_time = timedelta.total_seconds(d1 - d2)
print("diff time in seconds is : {}s".format(delta_time))
from datetime import datetime
from datetime import timedelta
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
delta_time = timedelta.total_seconds(d1 - d2)
print("diff time in seconds is : {}s".format(delta_time))
程序输出：
0:01:59.444000
diff time in seconds is : 119.444s
0:01:59.444000 diff time in seconds is : 119.444s
https://stackoverflow.com/questions/31929538/how-to-subtract-datetimes-timestamps-in-python/31929686
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