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[golang]将结构体方法序列化到JSON
source link: https://studygolang.com/articles/15646?amp%3Butm_medium=referral
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在写Restful API时,时常要序列化嵌套的资源,有时还需要定制序列化的字段。传统的方法只有进行结构体嵌套,然后还有将结构体转成map,剔除掉不需要的字段,比较繁琐。而 jsonfn 使用对象方法的思路,简化了这一流程。
一、序列化指定的字段
import "github.com/liamylian/jsonfn" type Book struct { Id int Title string AuthorId int } // 只序列化Id, Title // bytes = {"Id":1,"Title":"Jane Eyre"} bytes, _, := jsonfn.Marshal(Book{Id: 1, Title: "Jane Eyre", AuthorId: 2}, "Id", "Title") // 序列化所有字段 // bytes = {"AuthorId":2,Id":1,"Title":"Jane Eyre"} bytes, _, := jsonfn.Marshal(Book{Id: 1, Title: "Jane Eyre", AuthorId: 2}) bytes, _, := jsonfn.Marshal(Book{Id: 1, Title: "Jane Eyre", AuthorId: 2}, "*")
二、序列化嵌套资源
通过给Book和Author,分别添加Author和Country方法,可以在序列化Book时嵌套Author,而Author又嵌套了Country。
import ( "github.com/liamylian/jsonfn" "strconv" "time" ) type Book struct { Id int Title string AuthorId int CreatedAt time.Time } func (b Book) Author() Author { return Author{ Id: b.AuthorId, Name: "author" + strconv.Itoa(b.AuthorId), } } type Author struct { Id int Name string CountryId int } func (a Author) Country() Country { return Country{ Id: a.CountryId, Name: "country" + strconv.Itoa(a.CountryId), } } type Country struct { Id int Name string } func main() { book := Book{ Id: 1, Title: "Jane Eyre", AuthorId: 2, CreatedAt: time.Now(), } // output: // // { // "Id": 1, // "Title": "Jane Eyre", // "Author": { // "Id": 2, // "Name": "author2" // "Country": { // "Id": 0, // "Name": "country0" // } // } // } jsonStr, _ := jsonfn.Marshal(book, "Id", "Title", "Author{Id,Name}", "Author:Country{}") fmt.Println("%s", jsonStr) }
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