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The year * 10000 + month * 100 + day monotone?
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The year * 10000 + month * 100 + day monotone?
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Simple question: is year * 10000 + month * 100 + day always increasing? For example, today would is 20121011 and tomorrow is 20121012, which is 1 higher. Is this always the case? I've heard of some crazy stuff happening with dates and times before, but I'm no expert.
And just to preempt some responses - I know this is far from the best way to be handling dates/times. I can't use proper libraries for the problem I'm working on without jumping through some serious hoops, and I'd prefer a simple solution.
Yes it must. 0<day<100 and 0<month<100 always. Provided you use the full year, e.g. 2012 and not 12.
And you should not compare times from different zones, then you're fine.
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